F(3)=4x^2-5x+12

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Solution for F(3)=4x^2-5x+12 equation: 



(3)=4F^2-5F+12

We move all terms to the left:

(3)-(4F^2-5F+12)=0

We get rid of parentheses

-4F^2+5F-12+3=0

We add all the numbers together, and all the variables

-4F^2+5F-9=0

a = -4; b = 5; c = -9;
Δ = b2-4ac
Δ = 52-4·(-4)·(-9)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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